छंद

Maharashtra SET Examination Paper-I (Aptitude) Question with answers

 

1) There are flowers in a basket which are to be distributed to five persons standing in a row. The second person received half of the number of flowers given to the first person, the third person received half of the number of flowers received to the second person; the fourth person received half of the number of flowers received to the third person and the fifth person received half of the number of flowers received to the fourth person. If the fifth person received only one flower and there is no flower remaining in the basket, how many flowers were their in the basket ? 

(A) 31 (B) 32 (C) 16 (D) 15

Answer- Let the 1st person received x number of flowers,2nd person received x/2 number of flowers, 3rs received x/4 number of flowers, 4th received x/8 number of flowers,5th person received x/16 =1 number of flowers.

Let N number of flowers there were on the basket 

So N= x + x/2 + x/4 + x/8 + x/16 ........i)

But x/16= 1 implies that x=16 so substituting x=16 in equation i ) ,we get,

N=16+16/2 + 16/4 + 16/8 + 1 

   = 16+8+4+2+1

N= 31

So there were 31 flowers in the basket.

2)The area of a parallelogram is 128 cm^2 and its altitude is twice the corresponding base. What is the length of the base ? 

(A) 6 cm

(B) 7 cm 

(C) 12 cm

(D) 8 cm

Answer- Area of parallelogram = 128 cm^2

Its altitude is twice the corresponding base 

Let length of the base is L and that of altitude 2L.

  

Area of parallelogram= altitude×base 

                                  128= L× 2L=2L^2 

              therefore L^2. = 128/2 =64 

                                L=+8,-8

But length is never be negative so answer is 8 .

3) Let m be a 3 digit natural number such that the sum of the digits is 18 and the product of the digits is zero , Then which of the following is not true ? 

(A ) m is divisible by 3 

(B ) Either m is divisible by 10 or it is divisible by 101

( C ) Either m is odd or divisible by 11 

( D ) m is divisible by 9 and divisible by 13

Answer- Let x,y,z represents 3 digits of m naturalise number 

sum of these digits is 18,so x+y+z=18

and product of these digits is 0 

that is x × y × z = 0 but this possible only when one of the digit is zero means either x is 0 or y must be 0 or z must be 0, but here x can't be 0 because if x is 0 then m will be not a 3 digit number so x should be non zero.Suppose y is zero and x=9 ,z=9 cze 9+0+9= 18 which is divisible by 3 and when z =0 ,then x= 9 and y=9 therefore 9+9+0=18 which is divisible by and x×y×z=0 and moreover 909 is an odd number which is divisible 9 but not divisible by 13 also 990 is divisible by 9 but not divisible by 13.

Again 990 is divisible by 11 and 10,909 is odd and is divisible by 11 and 101.

So only 4rth option is correct option that is m is divisible by 9 and divisible by 13 

(Note that here we want an answer which is nit true .All the three options viz A,B,C are true only D is not true)

In the next blog I will give some more examples with detail answer